Is negative 1 comma 7 a

solution for the system of linear equations below? And they give us

the first equation is x plus 2y is equal to 13. Second equation is 3x minus

y is equal to negative 11. In order for negative

1 comma 7 to be a solution for the

system, it needs to satisfy both equations. Or another way of thinking about

it, x equals 7, and y– sorry, x is equal to negative 1. This is the x coordinate. X equals negative 1, and

y is equal to 7, need to satisfy both of

these equations in order for it to be a Solution. So let’s try it out. Let’s try it out with

the first equation. So we have x plus

2y is equal to 13. So if we’re thinking

about that, we’re testing to see if when x

is equal to negative 1, and y is equal to 7,

will x plus 2y equals 13? So we have negative

1 plus 2 times 7– y should be 7– this

needs to be equal to 13. And I’ll put a

question mark there because we don’t

know whether it does. So this is the same

thing as negative 1 plus 2 times 7 plus 14. That does, indeed, equal 13. Negative 1 plus 14, this is 13. So 13 does definitely equal 13. So this point it does, at least,

satisfy this first equation. This point does sit on the

graph of this first equation, or on the line of

this first equation. Now let’s look at

the second equation. I’ll do that one in blue. We have 3 times negative

1 minus y, so minus 7, needs to be equal

to negative 11. I’ll put a question

mark here because we don’t know whether

it’s true or not. So let’s see, we have 3 times

negative 1 is negative 3. And then we have minus 7 needs

to be equal to negative 11– I put the question mark there. Negative 3 minus 7,

that’s negative 10. So we get negative 10

equaling negative 11. No, negative 10 does

not equal a negative 11. So x equaling negative

1, and y equaling 7 does not satisfy

the second equation. So it does not sit on its graph. So this over here is not

a solution for the system. So the answer is no. It satisfies the

first equation, but it doesn’t satisfy the second. In order to be a

solution for the system, it has to satisfy

both equations.

thanks

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this is exactly what im experiencing right now. The coordinates satisfy only one equation. And i dont know what to do anymore.